
The provided context is irrelevant to the question. Based on general chemical principles, the answer is as follows.
Potassium chloride (KCl) has a total of 8 valence electrons. This figure is calculated by summing the valence electrons of the individual atoms that make up the compound.
Potassium (K) is an alkali metal in Group 1 of the periodic table, which means it has 1 valence electron. Chlorine (Cl) is a halogen in Group 17, and it has 7 valence electrons. When these two elements combine, the total count of valence electrons is the sum of their individual contributions: 1 from potassium plus 7 from chlorine equals 8.
In the formation of the ionic bond in potassium chloride, the potassium atom donates its single valence electron to the chlorine atom. This transfer allows the resulting potassium ion (K+) and chloride ion (Cl−) to each achieve a stable electron configuration with a full outer shell, resembling a noble gas.


